Your success in Microsoft 70-761 is our sole target and we develop all our 70-761 braindumps in a way that facilitates the attainment of this target. Not only is our 70-761 study material the best you can find, it is also the most detailed and the most updated. 70-761 Practice Exams for Microsoft MCSA 70-761 are written to the highest standards of technical accuracy.
♥♥ 2021 NEW RECOMMEND ♥♥
Free VCE & PDF File for Microsoft 70-761 Real Exam (Full Version!)
★ Pass on Your First TRY ★ 100% Money Back Guarantee ★ Realistic Practice Exam Questions
Free Instant Download NEW 70-761 Exam Dumps (PDF & VCE):
Available on:
http://www.surepassexam.com/70-761-exam-dumps.html
Q1. You have a database that stored information about servers and application errors. The database contains the following tables.
Servers
Errors
You need to return all error log messages and the server where the error occurs most often.
Which Transact-SQL statement should you run?
A. Option A
B. Option B
C. Option C
D. Option D
Answer: C
Q2. DRAG DROP
You have a database that includes the following tables:
You need to create a list of all customer IDs and the date of the last order that each customer placed. If the customer has not placed any orders, you must return the date January 1, 1900. The column names must be CustomerID and LastOrderDate.
Which four Transact-SQL segments should you use to develop the solution? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the answer area and arrange them in the correct order.
Answer:
Explanation:
Box 1: SELECT..COALESCE…
The COALESCE function evaluates the arguments in order and returns the current value of the first expression that initially does not evaluate to NULL.
Box 2: ..LEFT OUTER JOIN..
The LEFT JOIN (LEFT OUTER JOIN) keyword returns all rows from the left table (table1), with the matching rows in the right table (table2). The result is NULL in the right side when there is no match. A customer might have no orders so the right table must be allowed have a NULL value.
Box 3: ON c.custid = o.custid
We JOIN on the custID column, which is available in both tables. Box 4: GROUP BY c.custid
References:
https://technet.microsoft.com/en-us/library/ms189499(v=sql.110).aspx http://www.w3schools.com/sql/sql_join_left.asp
Q3. HOTSPOT
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
You are developing a database to track customer orders. The database contains the following tables: Sales.Customers, Sales.Orders, and Sales.OrderLines.
The following table describes the columns in Sales.Customers.
The following table describes the columns in Sales.Orders.
The following table describes the columns in Sales.OrderLines.
You need to create a database object that calculates the total price of an order including the sales tax. The database object must meet the following requirements:
- Reduce the compilation cost of Transact-SQL code by caching the plans and reusing them for repeated execution.
- Return a value.
- Be callable from a SELECT statement.
How should you complete the Transact-SQL statements? To answer, select the appropriate Transact-SQL segments in the answer area.
Answer:
Explanation:
Box 1: FUNCTION
To be able to return a value we should use a scalar function.
CREATE FUNCTION creates a user-defined function in SQL Server and Azure SQL Database. The return value can either be a scalar (single) value or a table.
Box 2: RETURNS decimal(18,2)
Use the same data format as used in the UnitPrice column.
Box 3: BEGIN
Transact-SQL Scalar Function Syntax include the BEGIN ..END construct.
CREATE [ OR ALTER ] FUNCTION [ schema_name. ] function_name
( [ { @parameter_name [ AS ][ type_schema_name. ] parameter_data_type [ = default ] [ READONLY ] }
[ ,...n ]
]
)
RETURNS return_data_type
[ WITH <function_option> [ ,...n ] ] [ AS ]
BEGIN
function_body
RETURN scalar_expression END
[ ; ]
Box 4: @OrderPrice * @CalculatedTaxRate Calculate the price including tax.
Box 5: END
Transact-SQL Scalar Function Syntax include the BEGIN ..END construct. References: https://msdn.microsoft.com/en-us/library/ms186755.aspx
Q4. DRAG DROP
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
You query a database that includes two tables: Project and Task. The Project table includes the following columns:
Task level is defined using the following rules:
You need to determine the task level for each task in the hierarchy.
Which five Transact-SQL segments should you use to develop the solution? To answer, move the appropriate Transact-SQL segments from the list of Transact-SQL segments to the answer area and arrange them in the correct order.
Answer:
Explanation:
Box 1: SELECT CAST (NULL AS INT) AS ParentTaskID, etc.
This statement selects all tasks with task level 0.
The ParentTaskID could be null so we should use CAST (NULL AS INT) AS ParentTaskID.
Box 2: UNION
We should use UNION and not UNION ALL as we do not went duplicate rows. UNION specifies that multiple result sets are to be combined and returned as a single result set.
Incorrect: Not UNION ALL: ALL incorporates all rows into the results. This includes duplicates. If not specified, duplicate rows are removed.
Box 3, Box 4, Box 5:
These statements select all tasks with task level >0.
References:
https://msdn.microsoft.com/en-us/library/ms180026.aspx
Q5. Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:
The tables include the following records: Customer_CRMSystem
Customer_HRSystem
Records that contain null values for CustomerCode can be uniquely identified by CustomerName.
You need to display a list of customers that do not appear in the Customer_HRSystem table.
Which Transact-SQL statement should you run?
A. Option A
B. Option B
C. Option C
D. Option D
E. Option E
F. Option F
G. Option G
H. Option H
Answer: D
Explanation:
EXCEPT returns distinct rows from the left input query that aren’t output by the right input query.
References: https://msdn.microsoft.com/en-us/library/ms188055.aspx
Q6. Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You create a table by running the following Transact-SQL statement:
You need to audit all customer data.
Which Transact-SQL statement should you run?
A. Option A
B. Option B
C. Option C
D. Option D
E. Option E
F. Option F
G. Option G
H. Option G
Answer: B
Explanation:
The FOR SYSTEM_TIME ALL clause returns all the row versions from both the Temporal and History table.
Note: A system-versioned temporal table defined through is a new type of user table in SQL Server 2021, here defined on the last line WITH (SYSTEM_VERSIONING = ON…, is designed to keep a full history of data changes and allow easy point in time analysis.
To query temporal data, the SELECT statement FROM<table> clause has a new clause FOR SYSTEM_TIME with five temporal-specific sub-clauses to query data across the current and history tables.
References: https://msdn.microsoft.com/en-us/library/dn935015.aspx
Q7. Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You create a table named Customers. Data stored in the table must be exchanged between web pages and web servers by using AJAX calls that use REST endpoint.
You need to return all customer information by using a data exchange format that is text- based and lightweight.
Which Transact-SQL statement should you run?
A. Option A
B. Option B
C. Option C
D. Option D
E. Option E
F. Option F
G. Option G
H. Option H
Answer: C
Explanation:
JSON can be used to pass AJAX updates between the client and the server.
Export data from SQL Server as JSON, or format query results as JSON, by adding the FOR JSON clause to a SELECT statement.
When you use the FOR JSON clause, you can specify the structure of the output explicitly, or let the structure of the SELECT statement determine the output.
References: https://msdn.microsoft.com/en-us/library/dn921882.aspx
Q8. Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:
The tables include the following records: Customer_CRMSystem
Customer_HRSystem
Records that contain null values for CustomerCode can be uniquely identified by CustomerName.
You need to create a list of all unique customers that appear in either table. Which Transact-SQL statement should you run?
A. Option A
B. Option B
C. Option C
D. Option D
E. Option E
F. Option F
G. Option G
H. Option H
Answer: E
Explanation:
UNION combines the results of two or more queries into a single result set that includes all the rows that belong to all queries in the union. The UNION operation is different from using joins that combine columns from two tables.
Q9. Note: This question is part of a series of questions that use the same or similar answer choices. An answer choice may be correct for more than one question in the series. Each question is independent of the other questions in this series. Information and details provided in a question apply only to that question.
You have a database that contains tables named Customer_CRMSystem and Customer_HRSystem. Both tables use the following structure:
The tables include the following records: Customer_CRMSystem
Customer_HRSystem
Records that contain null values for CustomerCode can be uniquely identified by CustomerName.
You need to display customers who appear in both tables and have a proper CustomerCode.
Which Transact-SQL statement should you run?
A. Option A
B. Option B
C. Option C
D. Option D
E. Option E
Answer: A
Explanation:
When there are null values in the columns of the tables being joined, the null values do not match each other. The presence of null values in a column from one of the tables being joined can be returned only by using an outer join (unless the WHERE clause excludes null values).
References: https://technet.microsoft.com/en-us/library/ms190409(v=sql.105).aspx
Q10. HOTSPOT
Note: This question is part of a series of questions that use the same scenario. For your convenience, the scenario is repeated in each question. Each question presents a different goal and answer choices, but the text of the scenario is exactly the same in each question in this series.
You query a database that includes two tables: Project and Task. The Project table includes the following columns:
You need to identify the owner of each task by using the following rules:
- Return each task’s owner if the task has an owner.
- If a task has no owner, but is associated with a project that has an owner, return the project’s owner.
- Return the value -1 for all other cases.
How should you complete the Transact-SQL statement? To answer, select the appropriate Transact-SQL segments in the answer area.
Answer:
Explanation:
Box 1: COALESCE
COALESCE evaluates the arguments in order and returns the current value of the first
expression that initially does not evaluate to NULL.
Box 2: T.UserID, p.UserID, -1
- Return each task’s owner if the task has an owner.
- If a task has no owner, but is associated with a project that has an owner, return the project’s owner.
- Return the value -1 for all other cases.
Box 3: RIGHT JOIN
The RIGHT JOIN keyword returns all rows from the right table (table2), with the matching rows in the left table (table1). The result is NULL in the left side when there is no match. Here the right side could be NULL as the projectID of the task could be NULL.
References:
https://msdn.microsoft.com/en-us/library/ms190349.aspx http://www.w3schools.com/Sql/sql_join_right.asp